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Serialization & Deserialization using JSON In C#


The very useful method of converting JSON object to .Net object and .Net object to Json object is using the JsonConvert. It converts Json objects to .Net object and with the Same property with value and .Net objects to equivalent JSON object.

In this article we will see how to serialize .NET type objects into JSON object and then deserialize data in the JSON format back into .NET types using the JsonConvert class.

What is JSON?

JSON (JavaScript Object Notation) is one lightweight and efficient data exchange format or we can say like JSON is most desirable data encoding format which allows fast exchanges of small amounts of data between client browsers and web services or web api.


JsonConvert class is in the namespace “Newtonsoft.Json” and for this namespace you need to add reference of Newtonsoft.Json dll or nuget package. You can install a Newtonsoft.Json nuget package by command “Install-Package Newtonsoft.Json” in package manager console.

If we want to convert .Net object to Json object then the SerializeObject() method will be used and when we want to convert Json object back to .Net object then DeserializeObject() method will be used from the JsonConvert class

JSON Serialization

Now lets see the JSON Serialization process with code example, we have an instance of Customer class as below

public class Customer
public int Id { get; set; }
public string Name { get; set; }
public string Email { get; set; }
public string PhoneNo { get; set; }

Now create an object of Customer class and initilize value of each properties. Then call SerializeObject() of JsonConvert class with passing Customer object.
See the below codesnippet

// Serializaion .Net Object
Customer customer = new Customer();
customer.Id = 1;
customer.Name = "Tarun Dudhatra";
customer.Email = "";
customer.PhoneNo = "5*9*9 5*8*5";

// Convert Customer object to JOSN encoded format
string jsonDataString = JsonConvert.SerializeObject(customer);


It will return the JSON string as below

{"Id":1,"Name":"Tarun Dudhatra","Email":"","PhoneNo":"5*9*9 5*8*5"}

JSON Deserialization

See the below JSON Deserialization process with code example, we have same Customer class string as below

{"Id":2,"Name":"FirstName LastName","Email":"","PhoneNo":"5*9*9 5*8*5"}

Now call the DeserializeObject() of JsonConvert class and pass the object type of Customer so it will deserialize it into Customer Class.
See the below codesnippet

Deserializaion JSON Object

string JSONObject = @"{ 'Id':2,'Name':'FirstName LastName','Email':'','PhoneNo':'5*9*9 5*8*5'}";

Customer customer = JsonConvert.DeserializeObject<Customer>(JSONObject);

Console.WriteLine( "Id : " + customer.Id);
Console.WriteLine( "Name : " + customer.Name);
Console.WriteLine( "Email: " + customer.Email);
Console.WriteLine( "Phone: " + customer.PhoneNo);

It will print the below out put on the screen

Id : 2
Name : FirstName LastName
Phone: 5*9*9 5*8*5

That’s it, in my upcoming article we will see other interesting stuff like this.

Tarun Dudhatra

Tarun is a writer of website. He is a software professional with hands on 10+ years of experience. Generally he writes an article about microsoft technology, Javascript, SQL Server and JQuery. Here he shares his notes, experiences, examples.